The elements of algebra1857 |
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Page 270
... cent . per annum ? 5 In this case M = 600 , n = 2 = 0 · 75 , λ = = 0.05 ; hence 100 P M 600 1 + nr 1 + 0.75 × 0.05 ... cent . but only the hundredth part of it . Thus for 4 per cent . r = 0 · 04 £ , for 5 per cent , r = 0 · 05 £ ; and so ...
... cent . per annum ? 5 In this case M = 600 , n = 2 = 0 · 75 , λ = = 0.05 ; hence 100 P M 600 1 + nr 1 + 0.75 × 0.05 ... cent . but only the hundredth part of it . Thus for 4 per cent . r = 0 · 04 £ , for 5 per cent , r = 0 · 05 £ ; and so ...
Page 271
... cent . per annum compound interest ? In this case R = 1'05 , n = 3 , M = 600 ; .. P = M 600 R " ( 1.05 ) 3 = = = £ 518-302 £ 518 . 6s . old . Ex . 2. Find the amount of 5 £ in 2 years at 3 per cent . , compound interest . Here P = 5 , R ...
... cent . per annum compound interest ? In this case R = 1'05 , n = 3 , M = 600 ; .. P = M 600 R " ( 1.05 ) 3 = = = £ 518-302 £ 518 . 6s . old . Ex . 2. Find the amount of 5 £ in 2 years at 3 per cent . , compound interest . Here P = 5 , R ...
Page 272
... cent . per annum , when the interest is due , and converted into principal , at the end of each half - year . Here P = 100 , r = 0.05 , n = 1 , .. Amount required = 100 × ( 1 + 0.025 ) 2 = 105-0625 £ , = 105 £ . 1s . 3d . 405. Required ...
... cent . per annum , when the interest is due , and converted into principal , at the end of each half - year . Here P = 100 , r = 0.05 , n = 1 , .. Amount required = 100 × ( 1 + 0.025 ) 2 = 105-0625 £ , = 105 £ . 1s . 3d . 405. Required ...
Page 280
... cent . per ann . compound interest ? P = In this case , A = 1 , R - 1 = 0.05 ; therefore the Present Value 1 0'05 = £ 20 , or 20 years ' purchase . A COR . 3. The Present Value of an Annuity of A £ payable m times per annum for n years ...
... cent . per ann . compound interest ? P = In this case , A = 1 , R - 1 = 0.05 ; therefore the Present Value 1 0'05 = £ 20 , or 20 years ' purchase . A COR . 3. The Present Value of an Annuity of A £ payable m times per annum for n years ...
Page 281
... cent . per ann . compound interest ? ( 1.05 ) 21-1 The Present Value for 21 years = = 12.82 £ ; ( 1.05 ) 1 × 0.05 and the Present Value for 7 years = ( 1.05 ) -1 ( 1.05 ) * x0 · 05 = 5'79 £ ; hence the value of the annuity for fourteen ...
... cent . per ann . compound interest ? ( 1.05 ) 21-1 The Present Value for 21 years = = 12.82 £ ; ( 1.05 ) 1 × 0.05 and the Present Value for 7 years = ( 1.05 ) -1 ( 1.05 ) * x0 · 05 = 5'79 £ ; hence the value of the annuity for fourteen ...
Common terms and phrases
algebraical quantities annuity Arithmetical Progression Binomial Theorem coefficient common denominator Comp contain continued fraction convergent cube root denary difference digits divided divisible divisor Edition equal equation EXERCISES expressed Extract the square factors Find the G.C.M. find the number Find the square find the sum Find the value given greater Greatest Common Measure Hence hour latter Least Common Multiple less lowest terms miles Mult multiplied N₁ negative nth root number of combinations number of terms numerator and denominator positive integers Post 8vo Present Value prime number proportion proposed quantities prove quadratic quadratic equation quotient radix ratio reduced remainder represented rule scale shew shillings square root ST JOHN'S COLLEGE subtracted suppose surd unknown quantities vols vulgar fraction whole number Woodcuts
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