The elements of algebra1857 |
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Page
... digits . " 260 , line 3 from bottom , for read n 1 n + 1 ' 324 , Ex . 26. The denominator of the first fraction should be √x + √æ3- instead of √x + √μ3 — a3 , 332 , Ex . 39. The answer a = √ ( √2 −1 ) should be a = ( √√ / 2 ...
... digits . " 260 , line 3 from bottom , for read n 1 n + 1 ' 324 , Ex . 26. The denominator of the first fraction should be √x + √æ3- instead of √x + √μ3 — a3 , 332 , Ex . 39. The answer a = √ ( √2 −1 ) should be a = ( √√ / 2 ...
Page
... digits . " ... 260 ) , line 3 from bottom , for read n + 1 n 324 , Ex . 26. The denominator of the first fraction should be √x + √x3 - qa instead of √æ + √æ3 — aa , 332 , Ex . 39 . The answer x = Ꮩ || ( √ / 2−1 ) should be a ...
... digits . " ... 260 ) , line 3 from bottom , for read n + 1 n 324 , Ex . 26. The denominator of the first fraction should be √x + √x3 - qa instead of √æ + √æ3 — aa , 332 , Ex . 39 . The answer x = Ꮩ || ( √ / 2−1 ) should be a ...
Page 23
... digits equal to the number of 9's recurring in the denominator of the fraction . If then , for instance , the vulgar fraction equivalent to 0.1212 & c . be required , we have 0.1212 & c . = 0.0101 & c.x12 . × 12 = 1 99 Again 0.123123 ...
... digits equal to the number of 9's recurring in the denominator of the fraction . If then , for instance , the vulgar fraction equivalent to 0.1212 & c . be required , we have 0.1212 & c . = 0.0101 & c.x12 . × 12 = 1 99 Again 0.123123 ...
Page 81
... digits in the root is obtained ; then the rest of the digits in the root may be determined by Division . For , let N represent the number whose square root , consisting of 2n + 1 digits , is required ; a .... .... the first n + 1 digits ...
... digits in the root is obtained ; then the rest of the digits in the root may be determined by Division . For , let N represent the number whose square root , consisting of 2n + 1 digits , is required ; a .... .... the first n + 1 digits ...
Page 82
... digits of the root are found ) divided by 2a will give the rest of the root required , x , increased by x2 2a * Now , since contains n digits , 2 has 2n at most ( Art . 154 ) . But , by the supposition , a is a number of 2n + 1 digits ...
... digits of the root are found ) divided by 2a will give the rest of the root required , x , increased by x2 2a * Now , since contains n digits , 2 has 2n at most ( Art . 154 ) . But , by the supposition , a is a number of 2n + 1 digits ...
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Common terms and phrases
according added algebraical amount annuity appears applied assume becomes binomial called cent chance coefficient combinations common common measure Comp compound contain continued convergent cube decimal denominator determined difference digits divided divisible divisor Edition equal equation EXERCISES expansion expressed Extract factors figures Find the value former four fraction given greater greatest happen Hence History hour increased integer interest latter least less manner means method miles multiplied negative obtained operation paid person places positive Present prime probability Progression proportion proposed prove quantity quotient ratio reduced remainder represented respectively result rule scale shew shillings side simple solution square root subtracted suppose surd taken things third true unit unknown quantities varies vols whole number
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